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# The midpoint of the segment of the line y = 4x + 3 which lies between the x-ax 1...

### Question

The midpoint of the segment of the line y = 4x + 3 which lies between the x-ax 1 is and the y-ax 1 is

### Options

A) ($$\frac{3}{2}$$, $$\frac{3}{2}$$)

B) ($$\frac{2}{3}$$, $$\frac{3}{2}$$)

C) ($$\frac{3}{8}$$, $$\frac{3}{2}$$)

D) (-$$\frac{3}{8}$$, $$\frac{3}{2}$$)

### Explanation:

y = 4x + 3
when x = 0, y = 3 $$\to$$ (0, 3)
when y = 0, x = -$$\frac{3}{4}$$ $$\to$$ ($$\frac{3}{4}$$, 0)
mid-point $$\frac{0 + (-{\frac{3}{4}})}{2}$$, $$\frac{3 + 0}{4}$$
-$$\frac{3}{8}$$, $$\frac{3}{2}$$

## Dicussion (1)

• y = 4x + 3
when x = 0, y = 3 $$\to$$ (0, 3)
when y = 0, x = -$$\frac{3}{4}$$ $$\to$$ ($$\frac{3}{4}$$, 0)
mid-point $$\frac{0 + (-{\frac{3}{4}})}{2}$$, $$\frac{3 + 0}{4}$$
-$$\frac{3}{8}$$, $$\frac{3}{2}$$