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If T = 2\(\pi\) \(\sqrt{\frac{L}{g}}\), make g the subject of the formula


Question

If T = 2\(\pi\) \(\sqrt{\frac{L}{g}}\), make g the subject of the formula

Options

A) \(\frac{4\pi L^2}{T}\)

B) \(\frac{4\pi^2 L^2}{T}\)

C) \(\frac{4\pi ^2 L}{T}\)

D) \(\frac{2\pi \sqrt{T}}{T}\)

The correct answer is C.

Explanation:

T = 2\(\pi\) \(\sqrt{\frac{L}{g}}\)
T2 = 4\(\pi^2 \frac{L}{g}\)
g = \(\frac{4\pi ^2 L}{T}\)

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