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# If T = 2$$\pi$$ $$\sqrt{\frac{L}{g}}$$, make g the subject of the formula

### Question

If T = 2$$\pi$$ $$\sqrt{\frac{L}{g}}$$, make g the subject of the formula

### Options

A) $$\frac{4\pi L^2}{T}$$

B) $$\frac{4\pi^2 L^2}{T}$$

C) $$\frac{4\pi ^2 L}{T}$$

D) $$\frac{2\pi \sqrt{T}}{T}$$

The correct answer is C.

### Explanation:

T = 2$$\pi$$ $$\sqrt{\frac{L}{g}}$$
T2 = 4$$\pi^2 \frac{L}{g}$$
g = $$\frac{4\pi ^2 L}{T}$$

## Discussion (2)

• T=2π√l/g
{T/2π}²={√l/g}²
T²/4π=l/g
T²g=4πl
g=4πl/T²

• T = 2$$\pi$$ $$\sqrt{\frac{L}{g}}$$
T2 = 4$$\pi^2 \frac{L}{g}$$
g = $$\frac{4\pi ^2 L}{T}$$