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What is the mean deviation 0f 3, 5, 8, 11, 12 and 21?



Dicussion (1)

  • mean(\(\bar{x}\)) = \(\frac{\sum x}{n}\)
    = \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\) = 10
    M.D = \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\)
    = \(\frac{28}{6}\)
    = 4.7

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