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What is the mean of the data t, 2t - 1, t - 2, 2t - 1, 4t and 2t + 2?


Question

What is the mean of the data t, 2t - 1, t - 2, 2t - 1, 4t and 2t + 2?

Options

A) 2t

B) 2t - 1

C) \(\frac{2}{3}\)t + 1

D) 2t - \(\frac{1}{3}\)

The correct answer is D.

Explanation:

\(\frac{t + 2t - 1 + t - 2 + 2t - 1 + 4t + 2t + 2}{6}\)
= \(\frac{12t - 2}{6}\)
= \(\frac {12t}{6}\) - \(\frac{2}{6}\)
= 2t - \(\frac{1}{3}\)

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