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3y = 4x - 1 and Ky = x + 3 are equations of two straight lines. If the two lines...


Question

3y = 4x - 1 and Ky = x + 3 are equations of two straight lines. If the two lines are perpendicular to each other, find K.

Options

A) -4/3

B) -3/4

C) 3/4

D) 4/3

The correct answer is A.

Explanation:

Grad of 3y = 4x - 1
y = 4x/3 - 1/3
Grad = 4/3
Grad of Ky = x + 3
y = x/k + 3/4
Grad = 1/k
Since two lines are perpendicular,
1/k = -3/4
-3k = 4
k = -4/3

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Dicussion (1)

  • Grad of 3y = 4x - 1
    y = 4x/3 - 1/3
    Grad = 4/3
    Grad of Ky = x + 3
    y = x/k + 3/4
    Grad = 1/k
    Since two lines are perpendicular,
    1/k = -3/4
    -3k = 4
    k = -4/3

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