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Make S the subject of the relation p = s + \(\frac{sm^2}{nr}\)


Question

Make S the subject of the relation
p = s + \(\frac{sm^2}{nr}\)

Options

A) s = \(\frac{nrp}{nr + m^2}\)

B) s = nr + \(\frac{m^2}{mrp}\)

C) s = \(\frac{nrp}{mr}\) + m2

D) s = \(\frac{nrp}{nr}\) + m2

The correct answer is D.

Explanation:

p = s + \(\frac{sm^2}{nr}\)
p = s + ( 1 + \(\frac{m^2}{nr}\))
p = s (1 + \(\frac{nr + m^2}{nr}\))
nr × p = s (nr + m2)
s = \(\frac{nrp}{nr + m^2}\)

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