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Find the sum to infinity of the following series 3 + 2 + 4 + 4/3 + 8/9 + 16/27 + .....



Dicussion (1)

  • Sholanke Oladimeji

    Sum to infinty of a gp = a/(1-r)
    a = 3
    r = 2nd term/1st term
    = 2/3
    So therfore
    3/(1-2/3)
    Solve whats in the bracket to get 1/3
    then 3/1/3 = 3 * 3
    = 9