**Paul and his friend, Peter went to buy an article costing ₦600. Peter had 10% of...**

### Question

Paul and his friend, Peter went to buy an article costing ₦600. Peter had 10% of the cost and Paul, 40% of the remainder. How much did they have altogether?### Options

The correct answer is C.

### Explanation:

Let's start by figuring out how much money Peter had. The cost of the article is ₦600 and Peter had 10% of this. In mathematics, percentage is a way of expressing a number as a fraction of 100. Therefore, to find out how much money Peter had, we calculate 10% of ₦600. We can do this by multiplying ₦600 by 0.1 (which is the decimal equivalent of 10%).

Doing this, we find that Peter had ₦60.

Next, let's figure out how much money Paul had. The problem tells us that Paul had 40% of the remainder. The remainder is what's left after Peter's portion has been subtracted from the cost of the article. So, we subtract Peter's ₦60 from the total cost of ₦600 to get ₦540.

Paul had 40% of ₦540. To find out how much this is, we multiply ₦540 by 0.4 (which is the decimal equivalent of 40%).

Doing this, we find that Paul had ₦216.

To find out how much money they had altogether, we add the amount of money that Peter had to the amount of money that Paul had. So, we add ₦60 (Peter's amount) to ₦216 (Paul's amount).

Doing this, we find that they had ₦276 altogether, which matches with Option C.

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Cost = 600

Peter = 10% of cost = 10/100 × 600= 60

Paul= 40% of remainder

remainder = 600-60= 540

:. 40% of 540 = 40/100 × 540= 216

Sum of Paul and peter = 216+ 60= 276