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The lengths of the sides of a right-angled triangle are ym, (3y - 1)m and (3y + ...



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  • Hyp²= opp²+ adj²
    Since hyp is the longest side of a right angled ∆ :.hyp= (3y +1)m
    (3y +1) ²= (y)² + (3y-1)²
    (3y+1) (3y+1)=(y)²+ (3y-1) (3y-1)
    9y²+ 6y+ 1 = y² + (9y² -6y +1)
    9y²+ 6y + 1 = 10y² -6y +1
    6y + 6y +1-1 =10y² -9y²
    12y =y²
    so therefore y²=12y
    Divide both sides by y
    Y(y)/y =12y/y
    Y=12

  • Hyp²= opp²+ adj²
    Since hyp is the longest side of a right angled ∆ :.hyp= (3y +1)m
    (3y +1) ²= (y)² + (3y-1)²
    9y²+ 6y+ 1 = y² + (9y² -6y +1)
    9y²+ 6y + 1 = 10y² -6y +1
    9y²-10y²= -6y - 6y +1-1
    -y²= -12y
    Y²=12y
    Divide both sides by y
    Y= 12

    1. Hello olusanya

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