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# Mr. Robson bought bags of orange for ₦2,500 each. He sold them for ₦90,000 a...

### Question

Mr. Robson bought bags of orange for ₦2,500 each. He sold them for ₦90,000 at a loss of 20%. How many bags of orange did he buy?

### Options

A)
60
B)
80
C)
50
D)
45 ## Discussion (3)

• Teniola

Bags of orange= x
Cp=2500x
So= 90,000
Loss= costprice _ selling price \cost price
20%= 2500x-90000/ 2500x
20/100=2500x-90000/2500x
0.2=2500x-90000/2500x
Cross multiply
0.2×2500x= 2500x-90000
500x= 2500x- 90000
Collect like terms
500x-2500x= 90000
2000x=90000
X,= 90000/2000
X=45

• Prosper Olusanya

Cost Price ( C.P)= 2500
Selling price (S.P) = Cost price - loss
Let the bag of oranges = X
C.P= #2500 × X= #2500X
Loss= 20% of C.P= 20/100 × 2500X= #500X
Since S.P= C.P- loss
:. S.P= 2500X - 500X
S.P = 2000X
From the question. Selling price = #90,000
:. 90,000= 2000X
Divide both sides by 2000
X= 45

• Bags of oranges=x
Cp=2500x
So= #90,000
Loss =20%
Cost price= selling price X 100/ 100-percentage loss
=90,000 X 100/ 100- 20
=90,000 X 100 /80
Cost price= 112,500
Number of bags of oranges= 112,500/2500
=45
:- The number of bags of oranges bought by Mr Tommy is 45