Home » Past Questions » Mathematics » Mr. Robson bought bags of orange for ₦2,500 each. He sold them for ₦90,000 a...

Mr. Robson bought bags of orange for ₦2,500 each. He sold them for ₦90,000 a...



Discussion (3)

  • Teniola

    Bags of orange= x
    Cp=2500x
    So= 90,000
    Loss= costprice _ selling price \cost price
    20%= 2500x-90000/ 2500x
    20/100=2500x-90000/2500x
    0.2=2500x-90000/2500x
    Cross multiply
    0.2×2500x= 2500x-90000
    500x= 2500x- 90000
    Collect like terms
    500x-2500x= 90000
    2000x=90000
    X,= 90000/2000
    X=45

  • Prosper Olusanya

    Cost Price ( C.P)= 2500
    Selling price (S.P) = Cost price - loss
    Let the bag of oranges = X
    C.P= #2500 × X= #2500X
    Loss= 20% of C.P= 20/100 × 2500X= #500X
    Since S.P= C.P- loss
    :. S.P= 2500X - 500X
    S.P = 2000X
    From the question. Selling price = #90,000
    :. 90,000= 2000X
    Divide both sides by 2000
    X= 45

  • Bags of oranges=x
    Cp=2500x
    So= #90,000
    Loss =20%
    Cost price= selling price X 100/ 100-percentage loss
    =90,000 X 100/ 100- 20
    =90,000 X 100 /80
    Cost price= 112,500
    Number of bags of oranges= 112,500/2500
    =45
    :- The number of bags of oranges bought by Mr Tommy is 45