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Given that log107 = x and log102 = y, evaluate without using tables, log1035...



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  • \(\log_{10} 7 = x\) and \(\log_{10} 2 = y\)
    \(\log_{10} 35 = \log_{10}(\frac{70}{2}) = \log_{10} 70 - \log_{10} 2\)
    \(\log_{10}(7 \times 10) - \log_{10}2\)
    \(\log_{10} 7 + \log_{10} 10 - \log_{10} 2\)
    \(= x + 1 - y = x - y + 1\)

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