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If hydrogen sulphide gas is passed into a solution of a pure iron chloride, a ye...


Question

If hydrogen sulphide gas is passed into a solution of a pure iron chloride, a yellow deposit appears. If the deposit is filtered, a pale green solution is left behind. The pale green solution is

Options

A)
dilute sulphuric acid
B)
dilute hydrochloric acid
C)
unreacted hydrogen sulphide in water
D)
iron (III) chloride
E)
Iron (II) chloride

The correct answer is E.

Explanation:

When hydrogen sulphide gas (\(H_2S\) is passed into a solution of pure iron chloride, a chemical reaction occurs. This reaction can be represented by the following equation:

\(2FeCl_3 + 3H_2S → Fe_2S_3(s) + 6HCl\)

In this reaction, iron (III) chloride (\(FeCl_3\) reacts with hydrogen sulphide to form a yellow deposit of iron (III) sulphide (\(Fe_2S_3\) and hydrochloric acid (\(HCl\).

When the yellow deposit of iron (III) sulphide is filtered, the remaining pale green solution is a result of the remaining iron (III) chloride reacting with water. This reaction can be represented by the following equation:

\(FeCl_3 + 3H_2O → Fe(OH)_3(s) + 3HCl\)

In this reaction, iron (III) chloride reacts with water to form a pale green precipitate of iron (III) hydroxide (\(Fe(OH)_3\) and hydrochloric acid. The hydrochloric acid will then react with the iron (III) hydroxide to form iron (II) chloride (\(FeCl_2\).

Therefore, the pale green solution is iron (II) chloride.


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