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In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon req...


Question

In a reaction: SnO + 2C → Sn + 2CO, the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is
[Sn = 119, O = 16, C = 12].

Options

A) 0.40 kg

B) 0.20 kg

C) 0.06 kg

D) 0.04 kg


The correct answer is C.

Explanation:

In the reaction: SnO2 + 2CO
From the equation above
2(12 g) carbon = 151 g SnO2
24 g carbon = 151 g SnO2
= 0.302 kg SnO2 = (24 ÷ 151g) × 0.0302 kg carbon = 0.048 kg carbon
Mass of coke is required not mass of carbon, so it is (0.048 × 100) ÷ 80 = 0.06


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Dicussion (1)

  • In the reaction: SnO2 + 2CO
    From the equation above
    2(12 g) carbon = 151 g SnO2
    24 g carbon = 151 g SnO2
    = 0.302 kg SnO2 = (24 ÷ 151g) × 0.0302 kg carbon = 0.048 kg carbon
    Mass of coke is required not mass of carbon, so it is (0.048 × 100) ÷ 80 = 0.06

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