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The oxidation state of Cr in K2Cr2O7 is



Dicussion (1)

  • K2Cr2O7
    +1×2+Cr2+(-2×7)=0
    +2+Cr2+14=0
    Make Cr2 the subject formula by substrating 2 from both side
    Cr2+14-2=0
    Cr2=12
    Divide both side by 2
    12/2=6
    Cr=+6
    Explanation provided by Jor Jagaba

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