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Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12...


Question

Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]

Options

A) They are both gases

B) Their molecules contain carbon

C) They have the same relative molecular mass

D) Both are denser than air


The correct answer is C.

Explanation:

Propane and Carbon(iv)oxide diffuse at thesame rate bcos they have thesame relative molecular mass
Propane C3H8=36+8=44g/mol
CO2=12+16×2=12+32=44g/mol
Explanation provided by Jor Jagaba

Explanation provided by Jonathan Hussaini


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