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# Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12...

### Question

Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0]

### Options

A) They are both gases

B) Their molecules contain carbon

C) They have the same relative molecular mass

D) Both are denser than air

### Explanation:

Propane and Carbon(iv)oxide diffuse at thesame rate bcos they have thesame relative molecular mass
Propane C3H8=36+8=44g/mol
CO2=12+16×2=12+32=44g/mol
Explanation provided by Jor Jagaba

Explanation provided by Jonathan Hussaini

## Discussion (6)

• They have the same relative molecular mass...
Propane ＝C3H8 ＝ (12x3) + (1x8) ＝ 36+8 ＝44g/mol
carbon (iv) oxide ＝ CO2 ＝12+(16x2) ＝12 + 32 ＝ 44g/mol

• Propane and Carbon(iv)oxide diffuse at thesame rate bcos they have thesame relative molecular mass
Propane C3H8=36+8=44g/mol
CO2=12+16×2=12+32=44g/mol
Explanation provided by Jor Jagaba

• Augustine

they have the same RMM

• Arogbonlo Augustine

zero