Nigerian Scholars » » How many moles of oxygen would contain $$1.204 \times 10^{24}$$ molecules? NB: Avogadro's constant (NA) $$= 6.02 \times 10^{23}$$...

# How many moles of oxygen would contain $$1.204 \times 10^{24}$$ molecules? NB: Avogadro's constant (NA) $$= 6.02 \times 10^{23}$$...

### Question

How many moles of oxygen would contain $$1.204 \times 10^{24}$$ molecules?
NB: Avogadro's constant (NA) $$= 6.02 \times 10^{23}$$

A) 1

B) 2

C) 3

D) 4

### Explanation:

$$6.02 \times 10^{23}$$ molecules is $$1$$ mole
$$1.204 \times 10^{24}$$ molecules will be:
$$\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}$$
$$\cfrac{1.204 \times 10}{6.02}$$ $$= \cfrac{12.04}{6.02} = 2$$ moles

## Dicussion (1)

• $$6.02 \times 10^{23}$$ molecules is $$1$$ mole
$$1.204 \times 10^{24}$$ molecules will be:
$$\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}$$
$$\cfrac{1.204 \times 10}{6.02}$$ $$= \cfrac{12.04}{6.02} = 2$$ moles