How many moles of oxygen would contain \(1.204 \times 10^{24}\) molecules? NB:...
Question
How many moles of oxygen would contain \(1.204 \times 10^{24}\) molecules?
NB: Avogadro's constant (NA) \(= 6.02 \times 10^{23}\)
Options
A)
1
B)
2

C)
3
D)
4
Related Lesson: Compounds | Quantitative Aspects of Chemical Change
The correct answer is B.
Explanation:
\(6.02 \times 10^{23}\) molecules is \(1\) mole
\(1.204 \times 10^{24}\) molecules will be:
\(\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\cfrac{1.204 \times 10}{6.02}\) \(= \cfrac{12.04}{6.02} = 2\) moles
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2 mole: if each molecule contains 1 mole, and since the Avogoro's constant is given, divide it by it to give you your answer
2mole
= 2MOLES
2 moles
2 moles
2
The ice and stem point on a thermometer are found to be 96.0mm apart. what temperature is recorded when the length of .mercury thread is 33.6mm above the ice point mark
\(6.02 \times 10^{23}\) molecules is \(1\) mole
\(1.204 \times 10^{24}\) molecules will be:
\(\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\cfrac{1.204 \times 10}{6.02}\) \(= \cfrac{12.04}{6.02} = 2\) moles
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