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How many moles of oxygen would contain \(1.204 \times 10^{24}\) molecules? NB:...


Question

How many moles of oxygen would contain \(1.204 \times 10^{24}\) molecules?
NB: Avogadro's constant (NA) \(= 6.02 \times 10^{23}\)

Options

A) 1

B) 2

C) 3

D) 4


The correct answer is B.

Explanation:

\(6.02 \times 10^{23}\) molecules is \(1\) mole
\(1.204 \times 10^{24}\) molecules will be:
\(\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\cfrac{1.204 \times 10}{6.02}\) \(= \cfrac{12.04}{6.02} = 2\) moles


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Discussion (2)

  • Okunola

    The ice and stem point on a thermometer are found to be 96.0mm apart. what temperature is recorded when the length of .mercury thread is 33.6mm above the ice point mark

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  • \(6.02 \times 10^{23}\) molecules is \(1\) mole
    \(1.204 \times 10^{24}\) molecules will be:
    \(\cfrac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
    \(\cfrac{1.204 \times 10}{6.02}\) \(= \cfrac{12.04}{6.02} = 2\) moles