Home » » The combustion of carbon(ii)oxide in oxygen can be represented by equation.2CO + O$$_2$$ → 2CO$$_2$$Calculate the volume of the resulting mixture at the end of the reaction if 50cm$$_3$$ ...

# The combustion of carbon(ii)oxide in oxygen can be represented by equation.2CO + O$$_2$$ → 2CO$$_2$$Calculate the volume of the resulting mixture at the end of the reaction if 50cm$$_3$$ ...

### Question

The combustion of carbon(ii)oxide in oxygen can be represented by equation.

2CO + O$$_2$$ → 2CO$$_2$$

Calculate the volume of the resulting mixture at the end of the reaction if 50cm$$_3$$ of carbon(ii)oxide was exploded in 100cm$$_3$$ of oxygen

### Options

A) 75cm$$^3$$

B) 125cm$$^3$$

C) 100cm$$^3$$

D) 50cm$$^3$$

## Dicussion (1)

• Given a balanced equation, the ratio of moles of the reactants and products is exactly the ratio of their volume provided they are gasses. This means:

2 volumes of carbon monoxide is required to react with 1 volume of oxygen to produce 2 volumes of carbon dioxide, provided they are all in gaseous state. This also means, in the reaction
50cm^3 of CO2 reacts with 25cm3 of O2 which leaves an excess 75cm3 remaining. The volume of gas produced is 50cm3. This leaves a total mixture of 125cm3.

2CO+O2=2CO2
In the ratio of 2:1:2
2vol CO reacts with 1vol O2
50cm³CO2 =(50×1)/2=25cm³

2vol. CO produces 2vol 2CO2
50cm³CO=(50×2)/2=50cm³

So back to the reaction
2CO +. O2. =. 2CO2
before
Reaction - 50cm³. 100cm³. _
During. -. 50. 25. _
After. _. 75. 50
So vol of total mixture after reaction=75+50
=125cm³