The combustion of carbon(ii)oxide in oxygen can be represented by equation.2CO + O\(_2\) → 2CO\(_2\)Calculate the volume of the resulting mixture at the end of the reaction if 50cm\(_3\) ...
Question
The combustion of carbon(ii)oxide in oxygen can be represented by equation.
2CO + O\(_2\) → 2CO\(_2\)
Calculate the volume of the resulting mixture at the end of the reaction if 50cm\(_3\) of carbon(ii)oxide was exploded in 100cm\(_3\) of oxygen
Options
A) 75cm\(^3\)
B) 125cm\(^3\)
C) 100cm\(^3\)
D) 50cm\(^3\)
The correct answer is B.
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Given a balanced equation, the ratio of moles of the reactants and products is exactly the ratio of their volume provided they are gasses. This means:
2 volumes of carbon monoxide is required to react with 1 volume of oxygen to produce 2 volumes of carbon dioxide, provided they are all in gaseous state. This also means, in the reaction
50cm^3 of CO2 reacts with 25cm3 of O2 which leaves an excess 75cm3 remaining. The volume of gas produced is 50cm3. This leaves a total mixture of 125cm3.
2CO+O2=2CO2
In the ratio of 2:1:2
2vol CO reacts with 1vol O2
50cm³CO2 =(50×1)/2=25cm³
2vol. CO produces 2vol 2CO2
50cm³CO=(50×2)/2=50cm³
So back to the reaction
2CO +. O2. =. 2CO2
before
Reaction - 50cm³. 100cm³. _
During. -. 50. 25. _
After. _. 75. 50
So vol of total mixture after reaction=75+50
=125cm³