Home » Past Questions » Chemistry » The combustion of carbon(ii)oxide in oxygen can be represented by equation.2CO + O\(_2\) → 2CO\(_2\)Calculate the volume of the resulting mixture at the end of the reaction if 50cm\(_3\) ...

The combustion of carbon(ii)oxide in oxygen can be represented by equation.2CO + O\(_2\) → 2CO\(_2\)Calculate the volume of the resulting mixture at the end of the reaction if 50cm\(_3\) ...


Question

The combustion of carbon(ii)oxide in oxygen can be represented by equation.

2CO + O\(_2\) → 2CO\(_2\)

Calculate the volume of the resulting mixture at the end of the reaction if 50cm\(_3\) of carbon(ii)oxide was exploded in 100cm\(_3\) of oxygen

Options

A) 75cm\(^3\)

B) 125cm\(^3\)

C) 100cm\(^3\)

D) 50cm\(^3\)

The correct answer is B.


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Dicussion (1)

  • Given a balanced equation, the ratio of moles of the reactants and products is exactly the ratio of their volume provided they are gasses. This means:

    2 volumes of carbon monoxide is required to react with 1 volume of oxygen to produce 2 volumes of carbon dioxide, provided they are all in gaseous state. This also means, in the reaction
    50cm^3 of CO2 reacts with 25cm3 of O2 which leaves an excess 75cm3 remaining. The volume of gas produced is 50cm3. This leaves a total mixture of 125cm3.

    2CO+O2=2CO2
    In the ratio of 2:1:2
    2vol CO reacts with 1vol O2
    50cm³CO2 =(50×1)/2=25cm³

    2vol. CO produces 2vol 2CO2
    50cm³CO=(50×2)/2=50cm³

    So back to the reaction
    2CO +. O2. =. 2CO2
    before
    Reaction - 50cm³. 100cm³. _
    During. -. 50. 25. _
    After. _. 75. 50
    So vol of total mixture after reaction=75+50
    =125cm³