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# Elements P, Q, R, S have 6, 11, 15, 17 electrons respectively, therefore,

### Question

Elements P, Q, R, S have 6, 11, 15, 17 electrons respectively, therefore,

### Options

A)
P will form an electrovalent bond with R
B)
Q will form a covalent bond with S
C)
R will form an electrovalent bond with S
D)
Q will form an electrovalent bond with S

### Explanation:

This question is asking which of the given options is correct based on the number of electrons in elements P, Q, R, and S. P has 6 electrons, Q has 11 electrons, R has 15 electrons, and S has 17 electrons.

Based on the number of electrons, we can determine the type of bond that each element is likely to form. Elements with similar electronegativity tend to form covalent bonds where they share electrons to achieve a stable octet. Elements with a large difference in electronegativity tend to form ionic or electrovalent bonds where one element donates an electron to the other to achieve a stable octet.

Element P has 6 electrons, so it needs 2 more electrons to achieve a stable octet. Element R has 15 electrons, so it needs to lose 1 electron to achieve a stable octet. Therefore, P and R are likely to form an electrovalent bond.

Element Q has 11 electrons, and element S has 17 electrons. They are both non-metals and have similar electronegativity, so they are likely to form a covalent bond by sharing electrons to achieve a stable octet. Therefore, option B is incorrect.

Option C is incorrect because R is likely to form an electrovalent bond with P, not with S.

Option D is correct because Q is likely to form an electrovalent bond with S due to their large difference in electronegativity. Q has 11 electrons and needs to gain 1 electron to achieve a stable octet, while S has 17 electrons and needs to lose 1 electron to achieve a stable octet. Therefore, option D is the correct answer.

In summary, based on the number of electrons in elements P, Q, R, and S, we can predict which type of bond they are likely to form. P and R are likely to form an electrovalent bond, while Q and S are likely to form an electrovalent bond. Therefore, option D is the correct answer.

## Dicussion (1)

• P 6 = 2, 4

Q 11 = 2, 8, 1

R 15 = 2, 8, 5

S 17 = 2, 8, 7

Given the above is the electronic arrangement of PQRS elements, Q will form an electrovalent bond with S. Without argument, D is the answer because electrovalency involves the transfer of electron. Already, Q is 11 with electronic configuration of 2, 8, 1, i.e. having 1 valence electron which is ready to be lost by the atom of element Q, also, S is 17, with electronic configuration of 2, 8, 7. There the 7 valence electron of S attracts that only 1 electron to attain a stable octet structure.