A given amount of gas occupies 10.0dm5 at 4atm and 273°C. The number of moles...
Question
A given amount of gas occupies 10.0dm5 at 4atm and 273°C. The number of moles of the gas present is [Molar volume of gas at s.t.p = 22.4dm\(^3\)]
Options
A) 0.89 mol
B) 1.90 mol
C) 3.80 mol
D) 5.70 mol
Related Lesson: Key Concepts and Summary | Gases
The correct answer is A.
Explanation:
PV = nRT
R = 0.08206(gas constant)
T = 273 + 273 = 546k(kelvin)
Therefore, n = PV/RT
n = 4 x 10/ 546 x 0.08206 = 0.8869, approx. 0.89mol
R = 0.08206(gas constant)
T = 273 + 273 = 546k(kelvin)
Therefore, n = PV/RT
n = 4 x 10/ 546 x 0.08206 = 0.8869, approx. 0.89mol
Explanation provided by David Gomba
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PV = nRT
R = 0.08206(gas constant)
T = 273 + 273 = 546k(kelvin)
Therefore, n = PV/RT
n = 4 x 10/ 546 x 0.08206 = 0.8869, approx. 0.89mol