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Calculate the percentage composition of oxygen in calcium trioxocarbonate(IV) [C...


Question

Calculate the percentage composition of oxygen in calcium trioxocarbonate(IV) [Ca=40, C=12, O=16]

Options

A) 16

B) 48

C) 40

D) 12


The correct answer is B.

Explanation:

Calcium trioxocarbonate (IV) = CaCO\(_3\)
Percentage of Oxygen = \(\frac{\text{Molar mass of 3O}}{\text{Molar mass of} CaCO_3}\) × 100%
Percentage of Oxygen = \(\frac{(3 \times 16)}{(40 + 12 + 48)}\)  x 100%
Percentage of Oxygen = \(\frac{48}{100}\) x 100%
Percentage of Oxygen = 48%


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Dicussion (1)

  • Calcium trioxocarbonate (IV) = CaCO\(_3\)
    Percentage of Oxygen = \(\frac{\text{Molar mass of 3O}}{\text{Molar mass of} CaCO_3}\) × 100%
    Percentage of Oxygen = \(\frac{(3 \times 16)}{(40 + 12 + 48)}\)  x 100%
    Percentage of Oxygen = \(\frac{48}{100}\) x 100%
    Percentage of Oxygen = 48%