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# To what volume must 300cm$$^3$$ of 0.60M sodium hydroxide solution be diluted to...

### Question

To what volume must 300cm$$^3$$ of 0.60M sodium hydroxide solution be diluted to give a 0.40M solution?

### Options

A) 450cm$$^3$$

B) 300cm$$^3$$

C) 200cm$$^3$$

D) 150cm$$^3$$

The correct answer is A.

### Explanation:

From the dilution law:
C$$_1$$V$$_1$$ = C$$_2$$V$$_2$$
C$$_1$$ = Initial Concentration of NaOH = 0.6M
V$$_1$$ = Initial Volume of NaOH = 300cm3
C$$_2$$ = Final Concentration of NaOH = 0.4M
V$$_2$$ = Final Volume of NaOH = ?
V$$_2$$ = $$\frac{C_1V_1}{C_2}$$
V$$_2$$ = $$\frac{0.6 \times 300}{0.4}$$
V$$_2$$ = 450 cm$$^3$$

Correct Computation as it follows the equation specified

## Dicussion (1)

• From the dilution law:
C$$_1$$V$$_1$$ = C$$_2$$V$$_2$$
C$$_1$$ = Initial Concentration of NaOH = 0.6M
V$$_1$$ = Initial Volume of NaOH = 300cm3
C$$_2$$ = Final Concentration of NaOH = 0.4M
V$$_2$$ = Final Volume of NaOH = ?
V$$_2$$ = $$\frac{C_1V_1}{C_2}$$
V$$_2$$ = $$\frac{0.6 \times 300}{0.4}$$
V$$_2$$ = 450 cm$$^3$$

Correct Computation as it follows the equation specified