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How many atoms are present in 6.0g of magnesium? [Mg = 24, N.A = 6.02 x 10 \(^{23}\)mol]...



Dicussion (1)

  • Dr. Chuma Odachi

    6.0 × 24 ÷ 6.02 × 10\(^{23}\) = 1.51 × 10\(^{22}\)