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A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]

Question

A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]

A)
CH
B)
CH2
C)
C2H3
D)
C2H5

Explanation:

element : C | H
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488
Multiply by 2 : 2.000 | 2.976
empirical formula is C2H3

Dicussion (1)

• element : C | H
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488

Multiply by 2 : 2.000 | 2.976

empirical formula is C2H3