A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]
Question
A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]Options
A) CH
B) CH2
C) C2H3
D) C2H5
Related Lesson: Derivation of Molecular Formulas | Composition of Substances and Solutions
The correct answer is C.
Explanation:
element : C | H
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488
Multiply by 2 : 2.000 | 2.976
empirical formula is C2H3
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element : C | H
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488
Multiply by 2 : 2.000 | 2.976
empirical formula is C2H3