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A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]


Question

A hydrocarbon containing 88.9% carbon has the empirical formula [H = 1 C = 12]

Options

A) CH

B) CH2

C) C2H3

D) C2H5


The correct answer is C.

Explanation:

element : C | H
Atomic Mass : 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488

Multiply by 2 : 2.000 | 2.976

empirical formula is C2H3


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Dicussion (1)

  • element : C | H
    Atomic Mass : 12.011 | 1.008
    mass in 100 g of compound 88.9 | 11.100
    we calculate the number of moles by dividing the mass by the atomic mass
    # moles in 100 g : 7.40155 | 11.01190
    molar ratio 7.40155 : 11.01190
    smallest No : 7.4015
    divide by the smallest No. : 1.000 : 1.488

    Multiply by 2 : 2.000 | 2.976

    empirical formula is C2H3