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Consider the following reaction equation:C2H4(g) + 3O2(g) \(\to\) 2CO2(g) + 2H2O...


Question

Consider the following reaction equation:

C2H4(g) + 3O2(g) \(\to\) 2CO2(g) + 2H2O(g)

The volume of CO2(g) produced at s.t.p when 0.05 moles of C2H4(g) was burnt in O2(g) is

[Molar Volume of gas = 22.4dm3]

Options

A) 1.12dm3

B) 2.24dm3

C) 3.72dm3

D) 4.48dm3


The correct answer is B.

Explanation:

1 mole of C2H4 produces 2 moles of CO2. 0.05 times 2 is equal to 1 mole. 1 mole of CO2 will be produced. Therefore the answer is 2.24dm3

Explanation provided by Fatoye Elijah


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Discussion (2)

  • Fatoye Elijah

    1 mole of C2H4 produces 2 moles of CO2. 0.05 times 2 is equal to 1 mole. 1 mole of CO2 will be produced. Therefore the answer is 2.24dm3

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  • \(\frac{\text{volume}}{\text{molar volume}}\) = 0.05

    = \(\frac{\text{volume}}{22.4}\) = 0.05 x 22.4 = 1.12dm3

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