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# Consider the following reaction equation:C2H4(g) + 3O2(g) $$\to$$ 2CO2(g) + 2H2O...

### Question

Consider the following reaction equation:

C2H4(g) + 3O2(g) $$\to$$ 2CO2(g) + 2H2O(g)

The volume of CO2(g) produced at s.t.p when 0.05 moles of C2H4(g) was burnt in O2(g) is

[Molar Volume of gas = 22.4dm3]

A) 1.12dm3

B) 2.24dm3

C) 3.72dm3

D) 4.48dm3

### Explanation:

1 mole of C2H4 produces 2 moles of CO2. 0.05 times 2 is equal to 1 mole. 1 mole of CO2 will be produced. Therefore the answer is 2.24dm3

Explanation provided by Fatoye Elijah

## Discussion (2)

• Fatoye Elijah

1 mole of C2H4 produces 2 moles of CO2. 0.05 times 2 is equal to 1 mole. 1 mole of CO2 will be produced. Therefore the answer is 2.24dm3

• $$\frac{\text{volume}}{\text{molar volume}}$$ = 0.05
= $$\frac{\text{volume}}{22.4}$$ = 0.05 x 22.4 = 1.12dm3