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A compound contains 40.0% carbon 6.7% hydrogen and 53.3% oxygen. If the molar ma...


Question

A compound contains 40.0% carbon 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180, find the molecular formula.

[H = 1, C = 12, O = 16]

Options

A) CH2O

B) C3H6O3

C) C6H12O6

D) C6H12O3


The correct answer is C.

Explanation:

C - 40% ; 40/12 = 3.33
H - 6.7% ; 6.7/1 = 6.7
O - 53.3% ; 53.3/16 = 3.33
C = 3.33/3.33 = 1
H = 6.7/3.33 = 2
O = 3.33/3.33 = 1
CH2O
(CH2O)n = 180
(12 + 2 + 16)~n = 180
30n = 180
n = 6
= C6H12O6

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Dicussion (1)

  • C - 40% ; 40/12 = 3.33
    H - 6.7% ; 6.7/1 = 6.7
    O - 53.3% ; 53.3/16 = 3.33
    C = 3.33/3.33 = 1
    H = 6.7/3.33 = 2
    O = 3.33/3.33 = 1
    CH2O
    (CH2O)n = 180
    (12 + 2 + 16)~n = 180
    30n = 180
    n = 6
    = C6H12O6