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What volume of gas is evolved at S.t.p if 2g of calcium trioxocarbonate (IV) is ...


Question

What volume of gas is evolved at S.t.p if 2g of calcium trioxocarbonate (IV) is added to a solution of hydrochloric acid?

[Ca = 40, C = 12, O = 16, Cl = 35.5, H = 1 Molar volume of agas at s.t.p = 22.4 dm3

Options

A) 112 cm2

B) 224 cm2

C) 448 cm2

D) 2240 cm2


The correct answer is C.

Explanation:

CaCO3(s) + 2HCl(aq) → CaCl2 + H2O(l) + CO2
The relative molecular mass of CaCO3 = 40 + 12 + 16 * 3 = 52 +48 = 100 ; Relative molecular mass of CO2 = 12 + 10 * 2 = 44
From the above equation, 100g of CaCO3reacts with 44g of CO2 at s.t.p. i.e 22.4 dm3
2g of CaCO3 will react with (2*22.4)/100 of CO2 = 0.448 dm3
0.448 dm3 = 0.448 * 1000 = 448cm3

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Dicussion (1)

  • CaCO3(s) + 2HCl(aq) → CaCl2 + H2O(l) + CO2
    The relative molecular mass of CaCO3 = 40 + 12 + 16 * 3 = 52 +48 = 100 ; Relative molecular mass of CO2 = 12 + 10 * 2 = 44
    From the above equation, 100g of CaCO3reacts with 44g of CO2 at s.t.p. i.e 22.4 dm3
    2g of CaCO3 will react with (2*22.4)/100 of CO2 = 0.448 dm3
    0.448 dm3 = 0.448 * 1000 = 448cm3

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