Home » Past Questions » Chemistry » 2H2 + O22 → H2+O ΔH = -571kJIn the equation above, how much heat will be libe...

2H2 + O22 → H2+O ΔH = -571kJIn the equation above, how much heat will be libe...


Question

2H2 + O22 → H2+O ΔH = -571kJ

In the equation above, how much heat will be liberated if 12.0g of hydrogen is burnt in excess oxygen?

Options

A) -1142 kJ

B) -571 kJ

C) +1142 kJ

D) -1713 kJ


The correct answer is D.

Explanation:

2H2 + O22 → H2+O ΔH = -571kJ
4.0g of Hydrogen burn in air to produce -571 kJ
∴ 12.0s of Hydrogen will burn in air to produce
(12 * -571)/4 = -1713kJ

More Past Questions:


Dicussion (1)

  • 2H2 + O22 → H2+O ΔH = -571kJ
    4.0g of Hydrogen burn in air to produce -571 kJ
    ∴ 12.0s of Hydrogen will burn in air to produce
    (12 * -571)/4 = -1713kJ

    Reply
    Like