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If a reaction is exothermic and there is a great disorder, it means that

Question

If a reaction is exothermic and there is a great disorder, it means that

Options

A)
the reaction is static
B)
the reaction is in a state of equilibrium
C)
there will be a large increase in free energy
D)
there will be a large decrease in free energy

Explanation:

An exothermic reaction is one that releases heat, resulting in a decrease in the system's enthalpy ($$ΔH 0$$. In order to determine the effect on free energy, we can use the Gibbs free energy equation:

$$ΔG = ΔH - TΔS$$

Since the reaction is exothermic, $$ΔH$$ is negative. The reaction also has a great disorder, making $$ΔS$$ positive. The temperature, $$T$$, is always positive (measured in Kelvin). Therefore, the term $$TΔS$$ will be positive.

Subtracting a positive value from a negative value ($$ΔH - TΔS$$ will result in a more negative value. This means that the change in Gibbs free energy, $$ΔG$$, is negative, indicating a large decrease in free energy. So, the correct answer should be Option D: there will be a large decrease in free energy.