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An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?...



Dicussion (1)

  • 2Fe2O3 → 4Fe + 3O2
    320g 224g 96g
    (70) / (100) x (80) / (1) 56g
    if 0.32kg of Fe293 contains 0.224 kg
    Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg

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