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A current of 10.0A was passed for 1 hour through a solution of copper (ll) sulph...


Question

A current of 10.0A was passed for 1 hour through a solution of copper (ll) sulphate between the copper electrodes. Which of the following observation would be correct?

(1 Faraday = 96,500 coulobms) (i) 0.186 mole of copper is dissolved from the anode. (ii) 0.372 mole of copper is deposited on the cathode. (iii) the original Cu2+ ion concentration of the solution remains unchanged. (iv) the original Cu2+ ion concentration of the solution decreases.

Options

A)
i and ii
B)
i and iii
C)
i and iv
D)
ii and iii
E)
ii and iv

The correct answer is B.


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