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The percentage of water of crystallization in ZnSO4. 7H2O is...



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  • Molecular mass of ZnSo4.7H2O = 65 + 32 + 16 × 4 + 7(1 × 2 + 16)
    = 97 + 64 + 126
    = 287 grams.

    Mass of Water of crystallization inZnSo4.7H2O (7H2O) = 7 × 18
    = 126 grams.
    Using the Formula,

    % of Water of Crystallization
    = (Mass of Water of Crystallization/Mass ofZnSo4.7H2O) × 100
    = (126/287) × 100
    = 43.91%.

    Thus, the % of Water of Crystallization inZnSo4.7H2O is 43.91%.

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  • Zn= 65, S=32, O= 16
    The molar mass of water is:
    7(2)+7(16)= 126g/mol
    The molar mass of the compound is:
    65+32+4(16)+7(2)+7(16)= 287g/mol
    Then the percentage of water is:
    126/287×100 =43.9%~44%

  • Fasina Nathaniel

    m.m of ZnSO4.7H20= 287
    mm of 7H20=126
    126/287*100= 43.9
    Approximately=44%

  • Mm of Zn≈65
    7(H₂O) = 126
    Mm of ZnSO₄ ≈ 161
    % of Water of crystallization;
    = 126
    ------------- • 100
    (126)+(161)
    ≈44%