What volume of (dm\(^3\)) of water will be added to 10dm\(^3\) of 2.0 mol/dm\(^3\) HCL acid solution to give a final solution of 0.5 mol/dm\(^3\)?...
Question
What volume of (dm\(^3\)) of water will be added to 10dm\(^3\) of 2.0 mol/dm\(^3\) HCL acid solution to give a final solution of 0.5 mol/dm\(^3\)?
Options
A)
30
B)
40
C)
20
D)
50
The correct answer is B.
Explanation:
To make a fixed amount of a dilute solution from a stock solution,
use the formula: C1V1 = C2V2
where: V1 = Volume of stock solution needed to make the new solution.
C1 = Concentration of stock solution.
V2 = Final volume of new solution.
C2 = Final concentration of stock solution
2 * 10 = 0.5 * V2
20 = 0.5V2
\(\frac{20}{0.5}\) = V2
= 40dm\(^3\)
More Past Questions:
Discussion
Other Subjects
- English Language
- Biology
- Mathematics
- Government
- Physics
- Economics
- Christian Religious Knowledge
- Commerce
- Geography
- Literature In English
- Accounts
- Agricultural Science
- General Paper
- Islamic Religious Knowledge
- History
- Further Mathematics
- Current Affairs
- Computer Studies
- Civic Education
- Math
- Reading
- Writing and Language
- Home Economics
- Igbo
- Hausa
- Yoruba
- French
- Fine Arts