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# What volume of (dm$$^3$$) of water will be added to 10dm$$^3$$ of 2.0 mol/dm$$^3$$ HCL acid solution to give a final solution of 0.5 mol/dm$$^3$$?...

### Question

What volume of (dm$$^3$$) of water will be added to 10dm$$^3$$ of 2.0 mol/dm$$^3$$ HCL acid solution to give a final solution of 0.5 mol/dm$$^3$$?

A)
30
B)
40
C)
20
D)
50

### Explanation:

To make a fixed amount of a dilute solution from a stock solution,

use the formula: C1V1 = C2V2

where: V1 = Volume of stock solution needed to make the new solution.

C1 = Concentration of stock solution.

V2 = Final volume of new solution.

C2 = Final  concentration of stock solution

2 * 10 = 0.5 * V2

20 = 0.5V2

$$\frac{20}{0.5}$$ = V2

= 40dm$$^3$$